Electronics and Communication Engineering - Electromagnetic Field Theory - Discussion
Discussion Forum : Electromagnetic Field Theory - Section 1 (Q.No. 11)
11.
A wave is propagated in a waveguide at frequency of 9 GHz and separation is 2 cm between walls Calculate group velocity for dominant mode.
Answer: Option
Explanation:
Vg . Vp = C2
where 
.
Discussion:
5 comments Page 1 of 1.
Hariom gupta said:
1 decade ago
Phase velocity shall be 5.42*10^8 m/sec.
And group velocity shall be 1.66*10^8 m/sec.
And group velocity shall be 1.66*10^8 m/sec.
(1)
Kesavan said:
1 decade ago
Any one please explain?
Dinakar said:
8 years ago
Give clarity for the answer.
Vinay said:
8 years ago
Please, anyone explain this.
NARENDRA KUMAR said:
8 years ago
Given that, f=9 GHZ, a=2cm=2/100 m,
So, fc=c/2a =3*10^8/(2*2/100)=7.5 Ghz.
After that put the value will get Vp and Vg.
So, fc=c/2a =3*10^8/(2*2/100)=7.5 Ghz.
After that put the value will get Vp and Vg.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers