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Electronics and Communication Engineering - Electromagnetic Field Theory

Exercise : Electromagnetic Field Theory - Section 15
16.

Assertion (A): When light falls at junction of p-n photodiode, its p side becomes positive and n side becomes negative.

Reason (R): When a photodiode is short circuited, the current in the external circuit flows from p side to n side.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not a correct explanation of A
A is true but R is false
A is false but R is true
Answer: Option
Explanation:
No answer description is available. Let's discuss.
17.
In what condition does BJT act like an open switch
cut off
saturation
active
both (b) and (c)
Answer: Option
Explanation:
No answer description is available. Let's discuss.
18.
In a JFET
gate source cut off voltage is equal to VDS
gate source cut off voltage is equal to pinch off voltage
gate source cut off voltage is twice the pinch off voltage
gate source cut off voltage is equal to negative pinch off voltage
Answer: Option
Explanation:
No answer description is available. Let's discuss.
19.
A power supply has full-load voltage of 20 V. What will be its no load voltage when its voltage regulation is 100%
0 V
10 V
20 V
40 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
20.
For a photo conductor with equal electron and hole mobilities and perfect ohmic contacts at the ends, an increase in the intensities of optical illumination results in
change in open circuit voltage
change in short circuit current
a reduction resistance
an increase of resistance
Answer: Option
Explanation:
No answer description is available. Let's discuss.
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