Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 24 (Q.No. 3)
3.
The Boolean expression (A + B) (A + C) (B + C) simplifies to
Discussion:
8 comments Page 1 of 1.
Nitin Singhal said:
9 years ago
By Using the property (X + YZ) = (X + Y) (X + Z).
So given expression reduces to (A' + B) (AB' + C').
Now multiply every term A'AB' + BAB' + (A' + B) C'.
Now the first two term reduces to zero. Therefore last expression will be the answer.
So given expression reduces to (A' + B) (AB' + C').
Now multiply every term A'AB' + BAB' + (A' + B) C'.
Now the first two term reduces to zero. Therefore last expression will be the answer.
Priyanka said:
8 years ago
(a'a+ab+c'a'+c'b)(b'+c').
= (1+ab+c'a+c'b)(b'+c').
= b' + c'.
So, the Ans should be (d).
= (1+ab+c'a+c'b)(b'+c').
= b' + c'.
So, the Ans should be (d).
(1)
Ram said:
7 years ago
I didn't understand this. Please make me clear by explaining the solution.
Mani said:
1 decade ago
= (a'c'+ba+bc').(b'+c').
= a'c'b'+a'c'+abc'+bc'.
= a'c'+bc'.
= c'(a'+b).
= a'c'b'+a'c'+abc'+bc'.
= a'c'+bc'.
= c'(a'+b).
Rajesh said:
9 years ago
Thank you @Nitin.
(1)
Vijaya said:
7 years ago
Thank you @Nitin.
Chaitanya said:
6 years ago
Thank you @Nitin.
Siddharth said:
4 years ago
Thans @Mani.
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