Electronics and Communication Engineering - Digital Electronics - Discussion


A 3 bit synchronous counter uses FF with propagation delay time of 20 ns each. The maximum possible time required for change of state will be.

[A]. 60 ns
[B]. 40 ns
[C]. 20 ns
[D]. None

Answer: Option B


No answer description available for this question.

Tausid said: (Apr 23, 2017)  
C is the correct answer. As it is synchronous counter it will take only 20 ns.

Tausid said: (Apr 24, 2017)  
The correct answer is C.

Pkn said: (Dec 21, 2017)  
C is correct. I also agree.

Parsya said: (Jan 15, 2018)  
The correct answer is C.

Srinu said: (Feb 12, 2018)  
May be, a synchronous counter needs a AND gate that might be considered.

Papdiv said: (Jan 1, 2019)  
The answer is C. I too agree.

Shiv said: (Jul 31, 2019)  
It is 3 bit counter require 2 ff so each ff delay is 20 therefore 20+20=40.

Surya said: (Aug 17, 2019)  
I agree @Shiv.

Arista said: (Apr 2, 2021)  
3 bit counter will need 3ff's @Shiv.

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