Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 2 (Q.No. 7)
7.
The number of unused states in a 4 bit Johnson counter is
Answer: Option
Explanation:
Total state = 2n = 24 = 16
Used state = 2n = 2 x 4 = 8
Unused state = 16 - 8 = 8.
Discussion:
5 comments Page 1 of 1.
Shubham said:
9 years ago
Can anyone explain that how it comes?
Saeed rahman said:
9 years ago
How to get the total Used states?
Suki said:
9 years ago
Actually, the required state for Johnson counter is 2n & for ring counter is n.
The total states are 2^n (no. of states).
Then unused states = no. of states - required states I.e. 16 - 8 = 8.
The total states are 2^n (no. of states).
Then unused states = no. of states - required states I.e. 16 - 8 = 8.
Suhas yadav said:
8 years ago
For johnson counter.
No of used states=2n; ===>2*4 = 8.
no of unused states = 2^n-2n ; ===>2^4-8 = 8.
No of used states=2n; ===>2*4 = 8.
no of unused states = 2^n-2n ; ===>2^4-8 = 8.
Husain said:
7 years ago
Total state = 2^n = 2^4 = 16.
Used state = 2*n = 2 x 4 = 8.
Unused state = 16 - 8 = 8.
Used state = 2*n = 2 x 4 = 8.
Unused state = 16 - 8 = 8.
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