Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 16 (Q.No. 35)
35.
The output voltage of 5-bit D/A binary ladder that has a digital input of 11010 (Assuming 0 = 0 V and 1 = + 10 V) is
Discussion:
5 comments Page 1 of 1.
Mahesh borate said:
9 years ago
Please provide the explanation for this question.
Abhishek said:
9 years ago
How to solve this?
Nawazshareef said:
9 years ago
Since it is a binary ladder type DAC
V = (16 + 8 + 2/2^5) * 10.
= 8.125V.
V = (16 + 8 + 2/2^5) * 10.
= 8.125V.
Nisha said:
5 years ago
Given that;
5- bit ladder D/A converter= 2^5,
Digital input= 11010.
Then,
11010= 1*2^4+1*2^3+0*2^2+1*2^1+0*2^0,
= 16+8+0+2+0,
=26.
V= 10v
Since, it is binary ladder type DAC
So,
V(output)= (16+8+2/2^5)*10
= 8.125v
That's all.
5- bit ladder D/A converter= 2^5,
Digital input= 11010.
Then,
11010= 1*2^4+1*2^3+0*2^2+1*2^1+0*2^0,
= 16+8+0+2+0,
=26.
V= 10v
Since, it is binary ladder type DAC
So,
V(output)= (16+8+2/2^5)*10
= 8.125v
That's all.
Vkmehta96 said:
4 years ago
Input voltage =2^5 = 32
V = 11010 puts 1=10v or 11010=26*10v = 260v,
V = 16*10+8*10+0*10+2*10+0*10 = 260v,
Output voltage= 260/32 = 8.125v.
V = 11010 puts 1=10v or 11010=26*10v = 260v,
V = 16*10+8*10+0*10+2*10+0*10 = 260v,
Output voltage= 260/32 = 8.125v.
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