Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 41)
41.
The number of distinct Boolean expression of 4 variables is
Answer: Option
Explanation:
22n = 224 = 216 .
Discussion:
8 comments Page 1 of 1.
Santosh Gupta said:
4 years ago
@Dhanya,
Your explanation is awesome. Thanks.
Your explanation is awesome. Thanks.
Raj said:
6 years ago
What you mean by expressions?
Vasista said:
7 years ago
The combination of minterms give the number of possible expressions.
2^n gives the number of possible values with n bits.
2^(2^n) gives the answer.
In this case 2^4=16 and 2^16 = 65536.
2^n gives the number of possible values with n bits.
2^(2^n) gives the answer.
In this case 2^4=16 and 2^16 = 65536.
Dhanya said:
7 years ago
How many minterms/maxterms possible = 2^n=2^4=16.
How many expressions/functions are possible = 2^2^4 =2^16 =6556.
How many expressions/functions are possible = 2^2^4 =2^16 =6556.
Saurav sharma said:
8 years ago
According to the explanation: 2^2^4 = 2^16.
But actually, it has to be: 2^2^4 = 2^8.
So how it will be A?
But actually, it has to be: 2^2^4 = 2^8.
So how it will be A?
Rishi Ram Panth said:
8 years ago
How is it A? Can you please explain?
Mega said:
8 years ago
The correct Answer is A.
Gaurang said:
9 years ago
The question here is a number of distinct boolean expressions, which are all min terms I suppose.
So, answer should be A.
So, answer should be A.
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