Electronics and Communication Engineering - Digital Electronics - Discussion

A cycle has both positive and negative half cycles. A number of cycles passing through a point in a given time we call it as a frequency.

So one, not gate conducts and change its state from one-half cycle to another half cycle. It conducts again and changes its state.

If final not gate at output conducts two times then only it produces a complete full cycle.

So, option C is correct.

Frequency of Ring Oscillator or Astable multivibrator is the inverse of the 2*n*propagation delay of each inverter.

So, few calculations will give 1 GHz as the answer. C is the correct answer.

Wrong answer it should be 1 Ghz.

Time taken to 0 to 1 is 100 psec.

Total 5 transition is 5x100 = 500 psec.

But time period becomes = 500+500 = 1000 psec.

2 GHz is right. Frequency is not time period.

Yes, C the is correct answer.