Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 5 (Q.No. 2)
2.
What will be conversion rate for a counter type A/D converter contains a 4 bit binary ladder and a counter driven by a 2 MHz clock. Then conversion time
Discussion:
5 comments Page 1 of 1.
Tanaya said:
6 years ago
Conversion rate = clock rate/2^n, where n=number of bits.
Which implies, conversion rate= 2 X (10^6)/2^4.
i.e (10^6)/8 => 125 X 10^3 seconds.
Therefore, Answer = B.
Which implies, conversion rate= 2 X (10^6)/2^4.
i.e (10^6)/8 => 125 X 10^3 seconds.
Therefore, Answer = B.
Ajay said:
7 years ago
Conversion time= frequecy/2^(n-1);
where n= number of bits
=>ct=2X10^6/2^3:since n=4;
=>ct=125 X 10^3.
where n= number of bits
=>ct=2X10^6/2^3:since n=4;
=>ct=125 X 10^3.
(1)
Parashu.kn said:
8 years ago
correct answer is,
CONVERSION TIME = 2^4/2*10^6.
= 8 MICRO SECOND.
CONVERSION RATE = 1/8*10^-6.
= 125 killo/SEC.
So answer is D.
CONVERSION TIME = 2^4/2*10^6.
= 8 MICRO SECOND.
CONVERSION RATE = 1/8*10^-6.
= 125 killo/SEC.
So answer is D.
Danish said:
8 years ago
conversion time= (2^n - 1)/fclk.
So, 7.5 micro seconds is the correct answer. D is correct.
So, 7.5 micro seconds is the correct answer. D is correct.
(1)
Regin said:
8 years ago
How? Please explain.
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