Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 6 (Q.No. 2)
2.
For a Mod 64 parallel counter we need
Answer: Option
Explanation:
26 = 64
So we need 6 flip-flops and (6 - 2) = 4 AND gates.
Discussion:
4 comments Page 1 of 1.
Tamil said:
1 decade ago
Anyone please explain this?
Rishi Ram Panth said:
8 years ago
Anyone, please explain this.
Aparna said:
7 years ago
Please explain this.
Vishnu said:
4 years ago
In mod64 count is up to 63==111111==6ff but ni and is required as I have implemented the same and tried it.
It's working without AND gates
It's working without AND gates
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