Electronics and Communication Engineering - Digital Electronics - Discussion

Fmax-max operating freq.
tpd- total propagation delay.
n - no.of Flipflops.
Fmax= 1/ n*tpd.
n= 1/ (10MHz*12ns).
n~ 8.
For mod counter its is 2^n.
so 2^8 =256.

Thanks to all of you for explaining the question.

Nice explanation @Akshay.

Exact calculation formula for the number of flip-flops used is,

F = 1/(N * tpd).

Where,
N-> No of flip flops.
F-> Frequency.
Tpd-> prop. Delay time.

At the last two lines. The formula used for the modulus will be (2^n).

Let's have an example.

I bought some eggs for 30 rupees, and I know the cost of 1 egg which is 5 rupee.

Then you can calculate the number of eggs I bought.

By dividing i.e. 30/5 = 6 eggs.

Ok.

In the same ways in the given question, propogation delay time for 1 JK flip-flop is given and the combinational resulting operating frequency is also given,

Then we can change the combinational frequency into time by the simple conversion I. E (time = 1 / frequency).

And after that, we can calculate the number of flip-flop used by dividing I. E (total time taken / propagation time delay of one flip-flop).

After that.

If n flip-flop is given then the total modulus can be solved by the formula (modulus^n).

Hope I can explain clearly.

@Sujideepika - TPD is propagation delay.

Can anyone explain what is tpd?

How they have calculated no of flip flops? Can anybody explain?