Electronics and Communication Engineering - Digital Electronics - Discussion

For ring counter, no. of states=N=no.of flipflops=5.
For johnson counter,no. of ststes = 2N = 2 * 5 = 10.
For general counter,no.of ststes = 2^N = 2^5 = 32.

For a n-bit,

[say for a counter, No : of states = N & No : of Flipflops = n]
Ring counter, no: of states = N = n.
no : of flipflops = n.

Johnson counter, no: of states = N = 2n.
no : of Flipflops = n.

General counter, no: of states = N = 2n.
no : of Flipflops = n.

For a ring counter, the number of flipflops is equal to a number of states.

A ring counter with 'n' flip flops will have 'n' states, as the ring counter is a re-circulation counter.

In a ring counter,
no.of states=no.of flipflops used.

In a johnson counter(switch tail or twisted counter),
no.of states= 2*no.of flipflops used.

A ring counter with 5 flip-flops will have 5 distinct states.

Here's why:
Ring Counter Function:
A ring counter is a type of sequential circuit where the output of each flip-flop is connected to the input of the next flip-flop circularly.

State Representation:
In a ring counter, only one flip-flop is in the "high" (or "1") state at any given time, with all other flip-flops in the "low" (or "0") state.

Number of States:
The number of states a ring counter can cycle through is equal to the number of flip-flops used in the circuit.

Example:
If you have 5 flip-flops, the counter will cycle through 5 distinct states where only one of the flip-flops is "1" at any given time, and the others are "0".

In ring counter, no of FF is equal to no of states.

Ring counter is N : 1 counter >>if it is 5, then 5 states.

Johnson counter is 2N : 1 counter>>here 10 states.

General counter is 2^N : 1 counter>>here 32 states.

In-ring counter, the number of the state depends on the number of the flip-flops.

Thanks a lot for all your explanation and solution.