Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 11 (Q.No. 11)
11.
The boolean expression for shaded area in the given figure is
AB + AC
ABC + ABC
ABC + ABC
None of these
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Rishi Ram Panth said:   8 years ago
How? Explain.

Swetha Baskaran said:   2 weeks ago
1st is the common area between a and b, and not c.
So, its AB(Cbar).
2nd is the common area between b and c, and not a.
So, its (Abar)BC.

Since these two are 2 different regions, they are combined with OR gate.
Therefore option C is correct.

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