Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 1 (Q.No. 8)
8.
A decade counter skips
binary states 1000 to 1111
binary states 0000 to 0011
binary states 1010 to 1111
binary states 1111 to higher
Answer: Option
Explanation:

A decade counter counts from 0 to 9. It has 4 flip-flops. The states skipped are 10 to 15 or 1010 to 1111.

Discussion:
16 comments Page 1 of 2.

Rohith vamshi said:   2 years ago
Decade =10, which means it has 10 locked states, which require 10 clock pulses.

It counts from 0000 to 1001 and restarts again from 0000 for the 11th clock pulse.
(2)

Ashma said:   9 years ago
Decade counter have 0 to 15 digit, but it counts only 0 to 9 digits, remaining 10 to 15 are skipped.
(1)

Raghava said:   6 years ago
Decad means 10 ie 0-9in binary 0000-1110.

In 4bit we can add to count 0-15.

So, the Decad line is up to 1110 so, it skips from1010-1111.
(1)

Vinay yadav said:   1 decade ago
Can anyone please explain me something more on this question.

Why we use example of 10-state only in the skipping?

Pankaj said:   1 decade ago
Because Decade counter count 10 digits from 0 to 9. After all item will be skipped.

Kalpish said:   1 decade ago
Please explain this.

Kishan kumar said:   1 decade ago
Decade counter means 0 to 9 other should not taken.

Arshad said:   1 decade ago
Why should D option is wrong? Could anyone clarify? It has also included 15 and above.

Deepak Beragud said:   10 years ago
After 9th count starts from 10th. I think so. Is it right?

Prarthi said:   10 years ago
@All.

D option is wrong because 10 to 15 digits are skipped in decade counter.


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