Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 4 (Q.No. 9)
9.
Decimal 8 in excess-3 code =
Answer: Option
Explanation:
Decimal 8 in excess 3 code = decimal 11 = 1011 in binary.
Discussion:
3 comments Page 1 of 1.
Rishi Ram Panth said:
8 years ago
How it is? Please explain how.
Ravi said:
8 years ago
It should be 10001, because excess-3 code is also a BCD code which is valid upto 0000 tob1001. Am I right?
Pavani said:
7 years ago
When we convert that 1000 binary to decimal we get 9. We have to add 3 to 9 then it becomes 11. So, the right answer is binary of 11.
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