Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 4 (Q.No. 44)
44.
A broadcast radio transmitter radiates 5 kW when the modulation percentage is 60. How much of this is carrier power?
Answer: Option
Explanation:
m = 1,
Discussion:
5 comments Page 1 of 1.
Maloy said:
5 years ago
Pt = Pc ( 1+m^2/2),
5000 = Pc ( 1+.60^2/2),
= 4.23Kw.
5000 = Pc ( 1+.60^2/2),
= 4.23Kw.
Jeeva said:
7 years ago
The value of m is 0.6 that is 60 percent.
Abrahamrufus said:
7 years ago
@Vishal.
How did you get 1.18?
How did you get 1.18?
Vishal said:
8 years ago
Pt=Pc(1+m^2/2),
5000=Pc(1+m^2/2),
Pc=5000/1.18=4.23 W.
5000=Pc(1+m^2/2),
Pc=5000/1.18=4.23 W.
Rehnu said:
8 years ago
The obtained answer here is 0.66. How is option D is answer? Please help me figure it out.
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