Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 2 (Q.No. 11)
11.
If the oscillator output is modulated by audio frequencies upto 10 kHz, the frequency range occupied by the side bands will be
Answer: Option
Explanation:
L = 50 mH, C = ln F
.
Discussion:
9 comments Page 1 of 1.
Anand said:
1 decade ago
How this be happen? Kindly tell us. Where you got L and C?
Jonathan said:
1 decade ago
Where did you get the 50 mH, as well as L and C from? Please, explain.
Mark Sarmiento said:
9 years ago
I think the solution is wrong, but. I think you can still see the correct answer because OPTION B, among all the choices only has the frequency range of 2 x 10 kHz.
Raghu said:
9 years ago
How it's done? Kindly explain to us from where you got L and c values.
Mukesh said:
9 years ago
bw = 2 * 10 khz = 20khz.
Again,
722khz - 702khz = 20 khz.
So, option B is right.
Again,
722khz - 702khz = 20 khz.
So, option B is right.
Swetha said:
9 years ago
Yes, option B correct. The difference between an upper frequency and lower frequency for all remaining options doesn't satisfy.
Rajashekar said:
8 years ago
Here, L=50 uH and C=1nF.
Rohan said:
8 years ago
fc-fm= 10 difference left side band.
fc+fm=10 difference right sideband.
fc+fm=10 difference right sideband.
(1)
SHADAN said:
7 years ago
Actually question is given half.
The Tuned -Circuit of the oscillator in an AM transmitter uses a 50 micro H Coil and 1 nF capacitor. Now if the oscillator output is modulated by audio frequency upto 10khz, then find the frequency range occupied by the sidebands.
The Tuned -Circuit of the oscillator in an AM transmitter uses a 50 micro H Coil and 1 nF capacitor. Now if the oscillator output is modulated by audio frequency upto 10khz, then find the frequency range occupied by the sidebands.
(1)
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