Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 12 (Q.No. 37)
37.
If the carrier of a 100 percent modulated AM wave is suppressed, the percentage power saving will be
50
100
150
Discussion:
6 comments Page 1 of 1.
Ammar said:
6 years ago
PC = 2/3Pt for m = 1.
2/3 = 66.6%.
2/3 = 66.6%.
Bharat Makwana said:
6 years ago
Ans is B.
Pt =Pc (1+m2/2),
m=1.
Pt =1.5 Pc.
Now PSB =m2 Pc /2.
m=1.
PSB = Pc /2=0.5Pc.
%Saving = (1.5-0.5)/1.5.
%Saving = 66.66%.
Pt =Pc (1+m2/2),
m=1.
Pt =1.5 Pc.
Now PSB =m2 Pc /2.
m=1.
PSB = Pc /2=0.5Pc.
%Saving = (1.5-0.5)/1.5.
%Saving = 66.66%.
Jbm said:
6 years ago
The correct is option is B.
Pt=Pc(1+m^2/2) and Psb=m^2/4.
Pt-Psb/Pt.
Pt=Pc(1+m^2/2) and Psb=m^2/4.
Pt-Psb/Pt.
CAML said:
7 years ago
The correct answer should be 33.3%.
Abhishek said:
7 years ago
Please explain the answer.
Rajashekar said:
8 years ago
The correct answer is B.
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