Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 14 (Q.No. 31)
31.
The percentage saving in power when the carrier and one of the sidebands are suppressed in an AM wave modulated to a depth of 100% will be nearly
Discussion:
2 comments Page 1 of 1.
Syed muzammil said:
4 years ago
Pt= pc(1+m^2/2) so pt = 1.5pc.
Psb= pc m^2/4 so 0.25pc,
Now;
(Pt-psb/pt)*100 that is equal to 83%.
Psb= pc m^2/4 so 0.25pc,
Now;
(Pt-psb/pt)*100 that is equal to 83%.
Rajashekar said:
6 years ago
Please explain the answer.
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