Electronics and Communication Engineering - Communication Systems - Discussion

Discussion Forum : Communication Systems - Section 9 (Q.No. 24)
24.
If e = 10 cos (2p x 108t + 20 cos 2p 103t). The bandwidth is
108 Hz
42 kHz
21 kHz
108 ± 103 Hz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.

Madhusuresh said:   9 years ago
Modulation index = 20,
wm = 2 * 3.14 * fm, fm = 2 * 3.14 * 10^3/2 * 3.14 = 10^3.
Bandwidth = 2(modulation indx + 1)fm, 2(20+1) * 10^3 = 42khz.

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