Electronics and Communication Engineering - Communication Systems - Discussion

Discussion Forum : Communication Systems - Section 4 (Q.No. 32)
32.
If Eb, the energy per bit of a binary digital signal is 10-6 watt sec. and the one sided power spectral density of the white noise N0 = 10-5 W/Hz, then the output SNR of the matched filter is
26 dB
10 dB
20 dB
13 dB
Answer: Option
Explanation:

O/P SNR = 10 log10 [2 x 10-6 x 10-5].

Discussion:
3 comments Page 1 of 1.

Ammar said:   6 years ago
SNR = 2Eb/No.

And then 10log(SNR).

The answer 13db is only valid if the noise and signal energies/power are swapped. Then you get 13db otherwise you get -7dB.

Gajendra kumar said:   7 years ago
O/p SNR = 10log (N0/bit power).

Clem said:   7 years ago
Shouldn't it be 10log10 (2*10^-5/10^-6)?

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