Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 6 (Q.No. 16)
16.
A sinusoidal signal with peak to peak amplitude of 1.536 volt is quantized into 128 levels using a mid-rise uniform quantizer. The quantization noise power is
Answer: Option
Explanation:
.
Discussion:
6 comments Page 1 of 1.
Bhavz said:
5 years ago
Why not Option B?
Kolii said:
7 years ago
Why was it divided by 12?
Shadan said:
8 years ago
Here, Δ = mp/L (Because peak to peak say).
So Δ =1.536/128 = 0.012
So Now,
Quantization noise power = 0.012*0.012/12.
= 12*10 to the power -6.
So Δ =1.536/128 = 0.012
So Now,
Quantization noise power = 0.012*0.012/12.
= 12*10 to the power -6.
Rajashekar said:
8 years ago
Answer is 1mV correct.
Sandy said:
8 years ago
NO C is the correct answer.
= 1.536/128,
= 0.012.
Now, squre of step size= 1.44 * 10^-4.
So, quantization noise power = 1.44^-4/12 and ans is= 12 * 10^-6.
= 1.536/128,
= 0.012.
Now, squre of step size= 1.44 * 10^-4.
So, quantization noise power = 1.44^-4/12 and ans is= 12 * 10^-6.
Sush said:
8 years ago
I think the answer is option B.
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