Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 20 (Q.No. 2)
2.
Probability of error in DPSK is less than PSK
Discussion:
2 comments Page 1 of 1.
Mukund said:
9 years ago
Answer should be false.
Sandeep k p said:
5 years ago
The correct option is B.
PSK is having less probability of error than DBPSK.
Pe DBPSK = 1/2 (e^ (-Eb/No) ) > Pe BPSK = Q (Eb/No) ^ (1/2).
PSK is having less probability of error than DBPSK.
Pe DBPSK = 1/2 (e^ (-Eb/No) ) > Pe BPSK = Q (Eb/No) ^ (1/2).
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