Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 24 (Q.No. 8)
8.
If in a broadcasting studio, a 1000 kHz carrier is modulated by an audio signal of frequency range 100-5000 kHz, the width of channel is __________ kHz.
Discussion:
3 comments Page 1 of 1.
Abdullah akhtar said:
8 years ago
In question message signal frequency is written (100-5000) khz is wrong. It should be 100-5000 hz only than the option D is correct.
Yooovi said:
8 years ago
@Rajendrakumar.
Where did you get the 5khz?
Where did you get the 5khz?
RAJENDRAKUMAR said:
9 years ago
i) Width of sideband = 5000 -100.
= 4900 Hz.
ii) - Max. frequency of USB = 1000 + 5 = 1005 kHz.
- Min. frequency of USB = 1000 + 0.1 = 1000.1 kHz.
iii) - Max. frequency of LSb = 1000 - 0.1= 999.9 kHz.
- Min. frequency of LSB = 1000 - 5 = 995 kHz.
iv) Width of channel = 1005 - 995 = 10 kHz.
= 4900 Hz.
ii) - Max. frequency of USB = 1000 + 5 = 1005 kHz.
- Min. frequency of USB = 1000 + 0.1 = 1000.1 kHz.
iii) - Max. frequency of LSb = 1000 - 0.1= 999.9 kHz.
- Min. frequency of LSB = 1000 - 5 = 995 kHz.
iv) Width of channel = 1005 - 995 = 10 kHz.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers