Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 22 (Q.No. 9)
9.
When Pc is the unmodulated carrier power and Pt is the total power in the modulated wave, then the maximum power in AM wave is
Discussion:
1 comments Page 1 of 1.
Arnab Bhattacharya said:
1 decade ago
In AM, Pt = Pc(1+ma^2/2); ma = modulation index (0 to 1).
Now Pt is maximum when ma is maximum (=1).
So, Pt(MAX) = Pc(1+1/2) = 3/2*Pc = 1.5 Pc. Option A is correct.
Now Pt is maximum when ma is maximum (=1).
So, Pt(MAX) = Pc(1+1/2) = 3/2*Pc = 1.5 Pc. Option A is correct.
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