Electronics and Communication Engineering - Communication Systems - Discussion

Discussion Forum : Communication Systems - Section 2 (Q.No. 27)
27.
In the absence of noise, if C is channel capacity in bits/s, δf is channel bandwidth in Hz and N is number of coding levels. Then
C = log2 N
C = (δf) log2 N
C = 2 (δf) log2 N
C = 0.5 (δf) log2 N
Answer: Option
Explanation:

Hartley law C = 2 δf log2N.

Discussion:
2 comments Page 1 of 1.

Tamil said:   8 years ago
I think the answer should be B.

Shadan said:   7 years ago
@Tamil.

1. Capacity for Noisy channel:-
C=Blog2(1+SNR)

2. Capacity for Noiseless channel:-
C=2Blog2M

Where C=Channel Capacity
B =Bandwith of channel
M=No.of Encoding level
and M=2to the power n.

So answer (C) is right.

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