Electronics and Communication Engineering - Communication Systems - Discussion
Discussion Forum : Communication Systems - Section 6 (Q.No. 48)
48.
In a superheterodyne receiver, having no RF amplifier, the IF is 455 kHz. The image frequency at 1000 kHz is
Answer: Option
Explanation:
Image frequency = 1000 - 455 = 545 kHz.
Discussion:
4 comments Page 1 of 1.
Sempaiklenny said:
1 decade ago
Must be +- twice the IF;
Hence, 1000+2*455 = 1910 or 1000-2*455 = 90.
Hence, 1000+2*455 = 1910 or 1000-2*455 = 90.
Shadab Akhtar said:
9 years ago
The answer should be 1910KHZ.
Because,
Fsi = 2IF + Fs
=> (2 * 455) + 1000
=> 1910
Because,
Fsi = 2IF + Fs
=> (2 * 455) + 1000
=> 1910
Deepu ac said:
9 years ago
Fsi = 2IF + Fs.
=> (2 * 455) + 1000,
=> 1910,
So the answer is C.
=> (2 * 455) + 1000,
=> 1910,
So the answer is C.
Ayush Kumar said:
8 years ago
Right answer is B because in question there is no rf stage.
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