Electronics and Communication Engineering - Automatic Control Systems - Discussion
Discussion Forum : Automatic Control Systems - Section 1 (Q.No. 26)
26.
Consider the systems with following open loop transfer functions
Answer: Option
Explanation:
. For the three systems the values of ξωn are 1.8, 2.5 and 2 respectively.
Hence values of T are 0.55, 0.4 and 0.5 respectively.
Discussion:
3 comments Page 1 of 1.
Anish kumar said:
8 years ago
See.
100/s(s+5) open loop transfer function.
100/s(s+5)/(1+100/s(s+5) ) = 100/s2+5s+100.
So coefficient of s = 2*si*wn = 5.
= si*wn=2.5.
Settling time = 4/2.5 = 1.6.
Likewise for 1 t settling will be 2.2, for 2 t settling will be 1.6, and for 3 t settling will be 2.
So(1) = 2.2.
(2) = 1.6.
(3) = 2.5.
So increasing order will be 2, 3, 1.
100/s(s+5) open loop transfer function.
100/s(s+5)/(1+100/s(s+5) ) = 100/s2+5s+100.
So coefficient of s = 2*si*wn = 5.
= si*wn=2.5.
Settling time = 4/2.5 = 1.6.
Likewise for 1 t settling will be 2.2, for 2 t settling will be 1.6, and for 3 t settling will be 2.
So(1) = 2.2.
(2) = 1.6.
(3) = 2.5.
So increasing order will be 2, 3, 1.
Arslan said:
8 years ago
@Hina khan.
Kindly explain it again. I did not understand.
Kindly explain it again. I did not understand.
Hina khan said:
9 years ago
Settling time will be 4T so increasing order of Ts will be 2, 3, 1.
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