Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 7 (Q.No. 26)
26.
The signal input to a given amplifier is made up of 100 mΩ signal power and 1 mΩ noise power. The amplifier contributes an additional 100 mΩ of noise and has a power gain of 20 dB. The noise factor is
Discussion:
1 comments Page 1 of 1.
Sruthi said:
10 years ago
Input SNR = 100 mW/1mW = 100.
Power gain = 20 dB = 100.
Output signal power = 100 mW*100.
Output Noise power = 1 mW*100+100 = 200mW.
Output SNR = (100*100)/200 = 50.
Noise Factor = (Input SNR)/(Output SNR) = 100/50 = 2.
Power gain = 20 dB = 100.
Output signal power = 100 mW*100.
Output Noise power = 1 mW*100+100 = 200mW.
Output SNR = (100*100)/200 = 50.
Noise Factor = (Input SNR)/(Output SNR) = 100/50 = 2.
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