Electronics and Communication Engineering - Analog Electronics - Discussion

Discussion Forum : Analog Electronics - Section 9 (Q.No. 35)
35.
A generator with an internal resistance of 600 Ω drives an amplifier whose input resistance is 400 Ω. The generator's open circuit voltages is 1 mV; the amplifier develops 100mV across an 8kΩ load. The input voltage to the amplifier is
0.1 m V
0.4 m V
1 m V
4 m V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Pramod said:   4 years ago
1mv is the input to generator (ie open circuit voltage ) then 1mv * 600/(600+400) = .4.

Sushanth said:   9 years ago
Kindly explain this.

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