Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 10 (Q.No. 26)
26.
Two 3Ω speakers in series will have a total impedance of
1 Ω
3 Ω
6 Ω
Discussion:
3 comments Page 1 of 1.
AL said:
3 years ago
By series, here they are side by side because speakers won't work when connected in series, thus it should be parallel.
LOi Bi said:
6 years ago
Speakers are connected in parallel.
So, R= (R1*R2) / (R1+R2).
R= (3*3) / (3+3) = 9/6 or 3/2 ohms.
So, R= (R1*R2) / (R1+R2).
R= (3*3) / (3+3) = 9/6 or 3/2 ohms.
Om prakash said:
10 years ago
Since speaker is in series, then how its equal is 3/2 ohm.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers