Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 16 (Q.No. 30)
30.
For a transistor if adc = 0.98 and emitter current IE is 2 mA, then collector current will be
Discussion:
9 comments Page 1 of 1.
Saurabh kumar said:
5 years ago
Option C is the correct answer.
Sankar said:
6 years ago
It is must be wkt α = Ic divide by Ie so Ic = 0.98*2 = 1.96mA.
Bici said:
6 years ago
It must be C. 1.96mA.
JOY SIDAYON said:
7 years ago
C is the correct answer, the fomula is Ic=a (dc) *Ie, Ic= (0.98*2mA) = 1.96mA.
Rajashekar said:
8 years ago
C is the Answer.
Prof.Arungandhi said:
8 years ago
Ic= α.Ie+Icbo.
Icbo value not given. So approximate value is ans C.
Icbo value not given. So approximate value is ans C.
KISHOR said:
9 years ago
The correct answer is C.
Ajit said:
9 years ago
Ic = alpha * Ie.
Mohit said:
9 years ago
Why not C?
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