Electronics and Communication Engineering - Analog Electronics - Discussion

Discussion Forum : Analog Electronics - Section 8 (Q.No. 11)
11.
In the circuit shown in the given figure, the current flowing through resistance of 100 Ω would be
8 mA
10 mA
20 mA
100 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Rajashekar balya said:   8 years ago
Opamp vi=2v.
So using virtually ground concept another terminal also same 2v so Vc=2v.
Vcc-ic.rc=0 10-2/1k=8ma.

Ssss said:   8 years ago
Anyone Explain it please.

Post your comments here:

Your comments will be displayed after verification.