Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 2 (Q.No. 15)
15.
A transistor with a = 0.9 and ICBO = 10 μA is biased so that IBQ = 90 μA. Then IEQ will be
Answer: Option
Explanation:
IEQ = ICQ + IBQ = 910 μA + 90 μA 
990 μA.
Discussion:
5 comments Page 1 of 1.
Shubham said:
8 years ago
Please explain in detail.
Rajashekar said:
8 years ago
ICQ = B * Ibq + {(1+B)*Icbo}.
Kattamamatha said:
9 years ago
But 910 + 90 = 1000 microamps right.
Ysakzz said:
1 decade ago
ICQ = ((a*IBQ)+(ICBO))/(1-a).
Sarani said:
1 decade ago
How we get ICQ value?
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