Electronics and Communication Engineering - Analog Electronics - Discussion

It's very helpful, thanks @Mani Kumar.

Thanks @Haritha and @Mani Kumar.

Is anyone tells the output of comparator irrespective of the duty cycle? I mean general comparator output.

I didn't know about this topic before referring here but with the elaborate explanations, I understand it better now. Thank yo all.

For those who wants to know about Pi/6.
Vm = 4V as Vpp = 8V.
Vref = V = 2V.

As V = Vm Sin(X) So, 2 = 4Sin(X).
Sin(X) = 0.5.
X = Sin Inverse (0.5).
X = 30 or Pi/6.

First, Duty Cycle is the ratio of the amount of time the device is on/conducting to the total period of the device.
The comparator will only be on if the input reaches 2 volts and higher. But as the input voltage goes down again beyond 2 volts, the comparator is off. This whole cycle takes 2π units so the period is 2π.
To get the total time the comparator is on, use this formula: integral_from{π/6} to {5π/6} 1dx. Divide that to the period 2π.

That's how you will get (1/3).

As per me at 4V(+ve peak) the value of X-axis is PI/2, then at 2V the value of X-axis will become PI/4 & 3PI/4.

If so then the duty cycle will become 1/4. i.e. 25% duty cycle. Please anyone confirm with this doubt.

Great explanation, thanks to all for the elaboration.

In general the form of sinusoidal signal is vmsin(x), where vm is peak voltage.

Given p-p is 8V, so vm=4v; so signal is 4sin(x) the period of sin wave is 2pi. equate 4sin(x) with 2 we get x=pi/6, 5pi/6; i.e sin(pi-pi/6) is also sin(pi/6), so on time is (pi-(2pi/6)).

Duty cycle = (4pi/6)/2pi = 1/3.

How at 2v phase is pi/6?