Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 4 (Q.No. 12)
12.
A transistor has a maximum power dissipation of 350 mW at an ambient temperature of 25°C. If derating factor is 2 mW/°C, the maximum power dissipation for 40°C ambient temperature is
Answer: Option
Explanation:
Derating improves reliability but does not affect maximum power dissipation.
Discussion:
2 comments Page 1 of 1.
Om Prakash said:
10 years ago
Correct answer is 350-15*2 = 320 mW.
Vidya said:
1 decade ago
The Derating factor of a transistor is the amount by which the power dissipation rating of a transistor falls when the transistor junction temperature increases.
If a transistors has a Derating factor of 2 mW/°C, then for each 1°C rise in junction temperature, the power rating of the transistor is reduced by 2mW. Then how it is 250?
If a transistors has a Derating factor of 2 mW/°C, then for each 1°C rise in junction temperature, the power rating of the transistor is reduced by 2mW. Then how it is 250?
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