Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 1 (Q.No. 5)
5.
A half wave diode circuit using ideal diode has an input voltage 20 sin ωt volts. Then average and rms values of output voltage are
and 10 V
and 10 V and 5 V and 5 VAnswer: Option
Explanation:
and VC = 0.5 x 20 = 10 V.
Discussion:
20 comments Page 2 of 2.
Saivasanth said:
8 years ago
@Dinesh.
Capacitor is used as it blocks dc component.
Capacitor is used as it blocks dc component.
AvishkarG said:
8 years ago
For HWR ckt. avg value=Vm/π and RMS value=Vm/2.
For FWR ckt avg value=2Vm/π and RMS value=Vm/√2.
For FWR ckt avg value=2Vm/π and RMS value=Vm/√2.
Sriram said:
7 years ago
I think the answer should be 40/π.
Satish m said:
7 years ago
How to get the answer? Please, anyone, help me.
Aman sajwan said:
7 years ago
Vdc =Vm/π, and Vrms=Vm/2.
Pen said:
6 years ago
For HWR;
Vrms = 1.57Vavg.
Vrms = 1.57Vavg.
Chandu anurag said:
6 years ago
The average value of half-wave rectifier: vm/pi.
The average value of full-wave diode: 2vm /pi.
The average value of full-wave diode: 2vm /pi.
(2)
Padmapriya said:
5 years ago
Answer b is correct Vrms= Vm/π=20/π,
Vavg=VM/2=20/2=10.
Vavg=VM/2=20/2=10.
Aleena said:
4 years ago
How will get 0.5?
Niranjan said:
3 years ago
For dc, half wave rectifier.
Vavg=Vm/π and Vrms=Vm/2.
and;
For dc, full wave rectifier.
Vavg=2Vm/π & Vrms=Vm/π2.
Vavg=Vm/π and Vrms=Vm/2.
and;
For dc, full wave rectifier.
Vavg=2Vm/π & Vrms=Vm/π2.
(9)
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