Electronics and Communication Engineering - Analog Electronics - Discussion

Discussion Forum : Analog Electronics - Section 1 (Q.No. 7)

Analog Electronics

In figure v₁ = 8 V and v₂ = 4 V. Which diode will conduct?

D₂ only

D₁ only

Both D₁ and D₂

Neither D₁ nor D₂

Answer: Option

Explanation:

D₁ will conduct and the output voltage will be about 7 V. Therefore D₂ will be reverse biased and will not conduct.

Discussion:

32 comments Page 2 of 4.

Surya said: 8 years ago

Both the diodes are conducting because p>n
p:positive terminal.
n:negative terminal.

This concept from pulse and digital circuits.

Kiran said: 8 years ago

@All.

First check current through both the diodes and ACC to the direction of current you can identify which diode is working.

Abhijit said: 7 years ago

(8-v)/1 +(4-v)/1=v/10,
v=5.71, where v is nodal voltage.
so D1 forward biased and D2 is reverse biased.
So, D1 is conducting.

Ramkamal said: 9 years ago

V1and V2 is not mentioned they are AC/DC. Secondly practically diode voltage drop 1v then both are forward biased.

Kayeschowdhury said: 10 years ago

B is the right answer. Because d1 conducts d2 will be in reverse biases mode. D2 will not conduct that time.

Shankar said: 1 decade ago

Option C is the correct answer. Because both diode are forward biased and above cutoff voltage.

Dhana said: 9 years ago

Suppose I will put same voltage at two nodes.

Two diodes are conduct or not please clarify.

Nimi said: 10 years ago

B is the correct. Because of D1 has more than D2 voltage range. Hence D1 only conduct.

Sharma said: 9 years ago

Could anyone explain clearly how diode (D1) alone conducts and not the other?

Vishnu said: 10 years ago

Output voltage will be 5V only (not 7V). So D2 will be reverse biased.

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