Electronics and Communication Engineering - Analog Electronics - Discussion

Discussion Forum : Analog Electronics - Section 1 (Q.No. 7)
7.
In figure v1 = 8 V and v2 = 4 V. Which diode will conduct?
D2 only
D1 only
Both D1 and D2
Neither D1 nor D2
Answer: Option
Explanation:

D1 will conduct and the output voltage will be about 7 V. Therefore D2 will be reverse biased and will not conduct.

Discussion:
32 comments Page 2 of 4.

Neha said:   8 years ago
@Nikkie

You will get V = 40/7 which is 5.7.

Hence, d1 will conduct and d2 will be reverse bias and won't conduct.
But from above statement how can tell that d1 will conduct?

Henna said:   8 years ago
How V is V/10?

Priya said:   8 years ago
Thanks for the explanation @Nikkie.

Nikkie said:   8 years ago
First take: I(1) + I(2) = I.
where I(1) = (V-8)/1k ohm.
similarly I(2) = (V-4)/1k ohm.
And I = V/10k ohm.

Next solve for 'V' ( USING KCL AT NODE V).
You will get V = 40/7 which is 5.7 something.

Hence, d1 will conduct and d2 will be reverse bias and won't conduct.

Surya said:   8 years ago
Both the diodes are conducting because p>n
p:positive terminal.
n:negative terminal.

This concept from pulse and digital circuits.

Kiran said:   8 years ago
@All.

First check current through both the diodes and ACC to the direction of current you can identify which diode is working.

Saurabh said:   1 decade ago
How ! both diode are forward than only d1 way ?

Ramkamal said:   9 years ago
V1and V2 is not mentioned they are AC/DC. Secondly practically diode voltage drop 1v then both are forward biased.

Sharma said:   9 years ago
Could anyone explain clearly how diode (D1) alone conducts and not the other?

Raushan said:   9 years ago
Assume both diodes are in forward bias, then after doing node analysis, the node at the intersection of 3 resistors, has the potential of 5 V (assuming cut off voltage 0.7V), which contradicts, so only one diode is in forward bias.


Post your comments here:

Your comments will be displayed after verification.