Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 2 (Q.No. 12)
12.
In a bridge rectifier circuit the rms value of input ac voltage is 10 V. The PIV across each diode is
Answer: Option
Explanation:
PIV is 2 x 10 = 14.14 V.
Discussion:
2 comments Page 1 of 1.
Pankhuri Saxena said:
7 years ago
Nice. Thank you @Mahesh.
Mahesh said:
9 years ago
The peak inverse voltage of the bridge wave rectifier = Vm,
and given Vrms = 10,
The relationship between Vm and Vrms is Vrms = Vm/Sqrt(2).
Vm = Sqrt(2) * 10,
= 1.414 * 10,
14.14.
and given Vrms = 10,
The relationship between Vm and Vrms is Vrms = Vm/Sqrt(2).
Vm = Sqrt(2) * 10,
= 1.414 * 10,
14.14.
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