Electronic Devices - Transistor Bias Circuits - Discussion
Discussion Forum : Transistor Bias Circuits - General Questions (Q.No. 18)
18.
Refer to the given figure. The most probable cause of trouble, if any, from these voltage measurements would be
Discussion:
5 comments Page 1 of 1.
Qwer said:
4 years ago
Ie = (1.1V-0.7V)/100kohm = 4mA,
Vc = 12-(4mA*1kohm) = 11.996.
If Re is open assuming Ie = Ic then Vc would be 12.
Vc = 12-(4mA*1kohm) = 11.996.
If Re is open assuming Ie = Ic then Vc would be 12.
Brane said:
5 years ago
Vc = Ic * Rc.
since Ic = Ie.
We find Ie first, where Ie = (1.1v-0.7v)/100kohm = 4mA,
Now that we have Ie,
Vc = 12v - (4mA*1kohm) = 8v.
So if Re is open.
You will not be able to calculate Ie or Ic hence it is 12v at Vc. I hope it helps.
since Ic = Ie.
We find Ie first, where Ie = (1.1v-0.7v)/100kohm = 4mA,
Now that we have Ie,
Vc = 12v - (4mA*1kohm) = 8v.
So if Re is open.
You will not be able to calculate Ie or Ic hence it is 12v at Vc. I hope it helps.
Khaldon said:
5 years ago
I think there's no problem here.
Potek said:
6 years ago
I think the problem is on the collector side.
Justme. said:
6 years ago
i think it should be no problem. Because all the values of the voltage are correct.
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