Electronic Devices - Transistor Bias Circuits - Discussion
Discussion Forum : Transistor Bias Circuits - General Questions (Q.No. 14)
14.
Refer to this figure. Assume that IC
IE. Find VE.



Discussion:
3 comments Page 1 of 1.
Pooja said:
8 years ago
Given Ic=Ie.
Ic = beta.Ib = 100*50*10 ki power -6.
Ic = 5*10 ki power -3 Amp.
i.e., Ie =5*10 ki power -3 Amp.
Ve = Ie.Re = 5*10 ki power -3 *500 = 2.5V.
Ic = beta.Ib = 100*50*10 ki power -6.
Ic = 5*10 ki power -3 Amp.
i.e., Ie =5*10 ki power -3 Amp.
Ve = Ie.Re = 5*10 ki power -3 *500 = 2.5V.
(1)
Mohammed Arif said:
1 decade ago
Put the value of Ib & B(current amp. factor) in below formula:
Ic = B*Ib;
Ic = 100*50 = 5000uA.
We know that,
VE = Ie*Re.
VE = 5000uA*500 ohm (bcoz Ie aprox = Ic).
VE = 2500000uV.
Convert in volt.
VE = 2.5 volt.
Ic = B*Ib;
Ic = 100*50 = 5000uA.
We know that,
VE = Ie*Re.
VE = 5000uA*500 ohm (bcoz Ie aprox = Ic).
VE = 2500000uV.
Convert in volt.
VE = 2.5 volt.
Sams said:
1 decade ago
IC = B*IB
VE = IC*RE = 2.5V
VE = IC*RE = 2.5V
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