Electronic Devices - Transistor Bias Circuits - Discussion

Discussion Forum : Transistor Bias Circuits - General Questions (Q.No. 11)
11.
What is the Q-point for a fixed-bias transistor with IB = 75 A, DC = 100, VCC = 20 V, and RC = 1.5 k?
VC = 0 V
VC = 20 V
VC = 8.75 V
VC = 11.25 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Vivek said:   5 years ago
If vbe is given in place of ib then what will the formula?

Please, anyone, tell me.

PRAVEEN SAGAR said:   1 decade ago
VCE=Vcc-IcRc (.'.VCE=Vc, Beta=Ic/Ib => Ic=Beta*Ib)

.'.Vc=Vcc-Beta*Ib*Rc
=20-100x75x10^(-6)x1.5x10^(-3)
=8.75V
(1)

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