Electronic Devices - Special-Purpose Diodes - Discussion
Discussion Forum : Special-Purpose Diodes - General Questions (Q.No. 24)
24.
Refer to this figure. If VIN decreases, IR will
Discussion:
2 comments Page 1 of 1.
Engr. Muntazir Hussain said:
1 decade ago
Vin = Vr+Vz.
Vz is constant.
So, Vin = Vr.
Vin = Ir*R.
Hence, when Vin decreases Ir will decrease.
Vz is constant.
So, Vin = Vr.
Vin = Ir*R.
Hence, when Vin decreases Ir will decrease.
Stranger said:
1 decade ago
Vin = Vr-Vz.
Vr = Vin-Vz.
When Vin decreases and Vz remains same, then Vr will decrease.
So, relatively Ir will decrease. [Vr = Ir.R].
Vr = Vin-Vz.
When Vin decreases and Vz remains same, then Vr will decrease.
So, relatively Ir will decrease. [Vr = Ir.R].
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