Electronic Devices - Special-Purpose Diodes - Discussion
Discussion Forum : Special-Purpose Diodes - General Questions (Q.No. 19)
19.
An 8.2 V zener has a resistance of 5
. The actual voltage across its terminals when the current is 25 mA is

Discussion:
7 comments Page 1 of 1.
Timotiwos yohanes said:
2 years ago
Thank you for explaining the answer.
Mega said:
8 years ago
Clear explanation @Padma Angmo.
Shiv rathour said:
8 years ago
Thanks @Padma.
(1)
Sheela said:
8 years ago
Thanks for the given explanations.
(1)
Nawazshareef said:
9 years ago
8.2 + 0.125 = 8.325, how this stem comes?
Padma angmo said:
10 years ago
Vz = 8.2 V.
Rs = 5 ohms.
Is = 25 mA = 0.025 A.
Vs = Is x Rs.
= 0.025 x 5 = 0.125 V.
Vin = Vz+Vs.
= 8.2 V + 0.125 V.
= 8.325 V answer.
Rs = 5 ohms.
Is = 25 mA = 0.025 A.
Vs = Is x Rs.
= 0.025 x 5 = 0.125 V.
Vin = Vz+Vs.
= 8.2 V + 0.125 V.
= 8.325 V answer.
(3)
Sandeep kumar gupta said:
1 decade ago
Voltage drop across 5 ohm is 5*25mA = 125mV
Then total voltage across terminal is 8.2+.125 = 8.325
Then total voltage across terminal is 8.2+.125 = 8.325
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