Electronic Devices - Semiconductors - Discussion
Discussion Forum : Semiconductors - General Questions (Q.No. 28)
28.
A silicon diode is forward-biased. You measure the voltage to ground from the anode at ________, and the voltage from the cathode to ground at ________.
Answer: Option
Explanation:
For silicon diodes, the built-in potential is approximately 0.7 V. Thus, if an external current is passed through the diode, about 0.7 V will be developed across the diode such that the P-doped region is positive with respect to the N-doped region and the diode is said to be "turned on" as it has a forward bias.
Therefore, 2.3 V - 1.6 V = 0.7 V. Hence the answer is correct.
Discussion:
8 comments Page 1 of 1.
JBM said:
7 years ago
For Germanium diode V.drop of 0.3v.
Rajavelu said:
8 years ago
Can anyone say the same for a Germanium?
Shiju said:
1 decade ago
Thank you bharat.
Brahma said:
1 decade ago
I did not understand it clearly. Could you please explain it clearly?
Er R K TRIPATHI said:
1 decade ago
Thank you bharat.
Ramu said:
1 decade ago
Thank you bharat.
Bharat said:
1 decade ago
Voltage from anode to ground is 2.3v and after diode it became 1.6v beacuse silicion diode drop 0.7v so ans B is right.
because no other option is avaliable here for 0.7v drop.
because no other option is avaliable here for 0.7v drop.
(1)
Shweta bhatt said:
1 decade ago
Why we measure voltage from anode at 2.3V and the voltage from cathode to ground at 1.6V ?
Secondly why diode do not allow to set a voltage across it more than 0.7V and for the same reason it is used to protect certain zero crossing detectors based on op amp circuit?
Secondly why diode do not allow to set a voltage across it more than 0.7V and for the same reason it is used to protect certain zero crossing detectors based on op amp circuit?
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