Electronic Devices - Semiconductor Diodes - Discussion
Discussion Forum : Semiconductor Diodes - General Questions (Q.No. 20)
20.
Calculate the power dissipation of a diode having ID = 40 mA.
Discussion:
20 comments Page 2 of 2.
SURENDRA SONI said:
1 decade ago
If we calculate power dissipation for ge type diode then it will be 0.3*40 = 12 mW.
If we calculate power dissipation for si type diode then it will be 0.7*40 = 28 mW.
So answer is A.
If we calculate power dissipation for si type diode then it will be 0.7*40 = 28 mW.
So answer is A.
Prabhu said:
1 decade ago
But here not specific silicon diode.
Jey said:
1 decade ago
0.7 voltage is default.
KIRAN said:
1 decade ago
P=V*I
= 0.7V*40mA
= 28mW.
Where 0.7V is the cut in voltage for the silicon diode.
No need to mention the name of the diode. we can take it for granted as Si is the best material for making electronic devices.
= 0.7V*40mA
= 28mW.
Where 0.7V is the cut in voltage for the silicon diode.
No need to mention the name of the diode. we can take it for granted as Si is the best material for making electronic devices.
Sharvi said:
1 decade ago
P=V*I
= 0.7 * 40mA
= 28 mA.
= 0.7 * 40mA
= 28 mA.
GUNA SEKAR said:
1 decade ago
Ya if nothing is mentioned we need to assume it is a silicon diode ram and bhiksham is correct answer.
Ram said:
1 decade ago
Yes if nothing is mentioned we need to assume it is a silicon diode.
Bhiksham said:
1 decade ago
I think if something is not mentioned we have to take it as Si as default.
PRASANNA said:
1 decade ago
But they have not stated its si diode.
Arindam said:
1 decade ago
Vd * Id = (0.7 * .040)W = .028 W = 28 mW
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