Electronic Devices - Semiconductor Diodes - Discussion
Discussion Forum : Semiconductor Diodes - General Questions (Q.No. 20)
20.
Calculate the power dissipation of a diode having ID = 40 mA.
Discussion:
20 comments Page 1 of 2.
KIRAN said:
1 decade ago
P=V*I
= 0.7V*40mA
= 28mW.
Where 0.7V is the cut in voltage for the silicon diode.
No need to mention the name of the diode. we can take it for granted as Si is the best material for making electronic devices.
= 0.7V*40mA
= 28mW.
Where 0.7V is the cut in voltage for the silicon diode.
No need to mention the name of the diode. we can take it for granted as Si is the best material for making electronic devices.
Niranjan Kumar said:
7 years ago
When not mention which material is used for diode, then Si should be assume.
So, power dissipation across the diode is Vd * Id =(0.7*0.040)w=0.028w = 28mw.
Where 0.7 is silicon cut in voltage.
So, power dissipation across the diode is Vd * Id =(0.7*0.040)w=0.028w = 28mw.
Where 0.7 is silicon cut in voltage.
(1)
SURENDRA SONI said:
1 decade ago
If we calculate power dissipation for ge type diode then it will be 0.3*40 = 12 mW.
If we calculate power dissipation for si type diode then it will be 0.7*40 = 28 mW.
So answer is A.
If we calculate power dissipation for si type diode then it will be 0.7*40 = 28 mW.
So answer is A.
M krishna naik said:
9 years ago
Silicon is the most commonly used diode hence we assume silicon if nothing is mentioned regarding diode name.
Vd * Id = (0.7 * 0.040)W = 0.028 W = 28 mW.
Vd * Id = (0.7 * 0.040)W = 0.028 W = 28 mW.
Rao said:
9 years ago
Since no specification of Diode, option D also could be the answer. If it's assumed Si diode then option A is right.
GUNA SEKAR said:
1 decade ago
Ya if nothing is mentioned we need to assume it is a silicon diode ram and bhiksham is correct answer.
Tejas said:
1 decade ago
Si is the most commonly used diode hence we assume Si if nothing is mentioned regarding diode name.
Tracy said:
9 years ago
The answer is A. Yeah, if it isn't stated, you have to use Silicon for able to get the 28 mW.
Jasmine said:
1 decade ago
Voltage drop of a diode is 0.7V.
Power dissipated = V x I = 0.7V x 40mA = 28mW.
Power dissipated = V x I = 0.7V x 40mA = 28mW.
Bhiksham said:
1 decade ago
I think if something is not mentioned we have to take it as Si as default.
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