Electronic Devices - Power Amplifiers - Discussion
Discussion Forum : Power Amplifiers - General Questions (Q.No. 6)
6.
A silicon power transistor is operated with a heat sink (
SA = 1.5ºC/W). The transistor, rated at 150 W (25ºC), has JC = 0.5º C/W, and the mounting insulation has CS = 0.6 ºC/W. What is the maximum power that can be dissipated if the ambient temperature is 50ºC and TJmax = 200 ºC?
SA = 1.5ºC/W). The transistor, rated at 150 W (25ºC), has JC = 0.5º C/W, and the mounting insulation has CS = 0.6 ºC/W. What is the maximum power that can be dissipated if the ambient temperature is 50ºC and TJmax = 200 ºC?Discussion:
4 comments Page 1 of 1.
Divya said:
1 decade ago
Based on formula.
Maximum power dissipation: (Junction temperature - Ambient temperature)/Thermal resistance of junction to ambient.
Maximum power dissipation: (Junction temperature - Ambient temperature)/Thermal resistance of junction to ambient.
(1)
Priya said:
10 years ago
Can you please send the formula?
Rohit kumar said:
9 years ago
Pd(max) = Tj(max) - Ta/Qjc + Qcs + Qsa = 150/2.6 = 57.69.
Nichole said:
4 years ago
Pd = (Tj- Ta)/ (θjc+θcs+θsa),
Pd = (200-50) / (0.5 + 0.6 + 1.5),
Pd = 57.7 W.
Pd = (200-50) / (0.5 + 0.6 + 1.5),
Pd = 57.7 W.
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