Electronic Devices - Power Amplifiers - Discussion
Discussion Forum : Power Amplifiers - General Questions (Q.No. 23)
23.
What transformer turns ratio is required to match an 8-
speaker load so that the effective load resistance seen at the primary is 12.8 k?
speaker load so that the effective load resistance seen at the primary is 12.8 k?Discussion:
6 comments Page 1 of 1.
Rashmi Byakod said:
1 decade ago
Np/Ns = Square root (Zp/Zs).
Amarjyoti Sarmah said:
1 decade ago
Can anyone can solved this for me:
A transformer has 1:6 turns ratio and a secondary load resistance of 470 ohm. What will be load resistance as seen by the source?
Also, calculate the turns ratio reqd. To match 80 ohm source to 320 ohm load?
Please also give the necessary details with formula?
A transformer has 1:6 turns ratio and a secondary load resistance of 470 ohm. What will be load resistance as seen by the source?
Also, calculate the turns ratio reqd. To match 80 ohm source to 320 ohm load?
Please also give the necessary details with formula?
Sri said:
1 decade ago
Effective load resistance = ((N1/N2)^2)*(actual resistance).
Ajay said:
1 decade ago
Primary effective resistance = Load resistance*(n2^2/n1^2);
Here load resistance = 8;
Primary resistance = 12.8 k ohm.
So 12.8x10^3 = 8*(n2^2/n1^2);
N2^2/n1^2 = 12.8 k/8;
N2^2/n1^2 = 1600;
So n1 = 1; n2 = 40.
Here load resistance = 8;
Primary resistance = 12.8 k ohm.
So 12.8x10^3 = 8*(n2^2/n1^2);
N2^2/n1^2 = 12.8 k/8;
N2^2/n1^2 = 1600;
So n1 = 1; n2 = 40.
SK said:
4 years ago
Rl' = 12.8*10^3,
RL = 8.
N = √(12.8*10^3/8).
= 40.
RL = 8.
N = √(12.8*10^3/8).
= 40.
SK said:
4 years ago
Rl' = 12.8*10^3,
RL = 8.
N = √(12.8*10^3/8).
= 40.
RL = 8.
N = √(12.8*10^3/8).
= 40.
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